Which of the following is the correct structu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) -glucose is the naturally occurring isomer where the $-OH$ group on the chiral carbon furthest from the aldehyde group (i.e.,$C-5$) is on the righ

Vedclass · Accepted Answer

Vedclass · Answer

(A) -glucose is the naturally occurring isomer where the $-OH$ group on the chiral carbon furthest from the aldehyde group (i.e.,$C-5$) is on the right side in the Fischer projection.$L$-glucose is the enantiomer of $D$-glucose.To obtain the structure of $L$-glucose,we must invert the configuration at every chiral center $(C-2, C-3, C-4, C-5)$ of $D$-glucose.In $D$-glucose,the $-OH$ groups are at: $C-2$ (right),$C-3$ (left),$C-4$ (right),$C-5$ (right).Therefore,in $L$-glucose,the $-OH$ groups must be at: $C-2$ (left),$C-3$ (right),$C-4$ (left),$C-5$ (left).This corresponds to the structure where the $-OH$ group on $C-5$ is on the left,which is the definition of the $L$-configuration.

Which of the following is the correct structure of $L$-glucose?

Similar Questions

In a transformer,the number of turns in primary and secondary are $500$ and $2000$ respectively. If current in primary is $48 \ A$,the current in the secondary is........$A$

The wavelength of the light used in Young's double slit experiment is $\lambda$. The intensity at a point on the screen is $I$,where the path difference is $\lambda/6$. If $I_0$ denotes the maximum intensity,then the ratio of $I$ and $I_0$ is

$A$ candle of diameter $d$ is floating on a liquid in a cylindrical container of diameter $D$ $(D >> d)$ as shown in the figure. If it is burning at the rate of $2 \, cm/hour$,then the top of the candle will

An electron makes a transition from orbit $n = 4$ to the orbit $n = 2$ of the hydrogen atom. The wave number of the emitted radiation ($R =$ Rydberg's constant) will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module